12x^2+63x-1380=0

Solution for 12x^2+63x-1380=0 equation:

12x^2+63x-1380=0

a = 12; b = 63; c = -1380;
Δ = b2-4ac
Δ = 632-4·12·(-1380)
Δ = 70209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{70209}=\sqrt{9*7801}=\sqrt{9}*\sqrt{7801}=3\sqrt{7801}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-3\sqrt{7801}}{2*12}=\frac{-63-3\sqrt{7801}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+3\sqrt{7801}}{2*12}=\frac{-63+3\sqrt{7801}}{24}
$